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Vitesse « nominale » ou nombre de tours/mn nominal 27 août 2013 17:13, par ernestptSuper. j’avais un scan du manuel en français, mais malgré tout le respect que je dois au collègue qui l’a scanné, les graphes passent très mal, notamment celui qui tu montre.
Je suis allé sur le site, ... sans trouvé évidemment ce que tu nous montres, cependant j’ai ceci qui peut enrichir tes éléments (mais attention au copyright, hein ?).
"To estimate fuel consumption
This example is the 6CX-ETE, 420hp @ 2700 rpm, engine
To work out an approximate fuel consumption : select the rpm from along the bottom of the chart and go up to the propeller power curve, go to the right and select the horsepower (hp).
Write it down.
Back to the vertical rpm line, go up to where it intersects the specific fuel consumption curve. Go to the right and select the specific fuel consumption (sfc) in grams per horsepower per hour, write it down.
Multiply your hp figure by your sfc figure and divide by *850, this is the fuel consumption in litres per hour.
U.S. operators may multiply the hp x sfc and divide by *3220 for fuel consumption in U.S. gallons per hour.
The example shows that at 2300rpm, the propeller absorbs 250hp x 165sfc divided by 850 = 48.5litres per hour.
or :
2300rpm, 250hp x 165sfc divided by 3220 = 12.8 U.S. gallons per hour.
* (The specific gravity of diesel is given as 850 grams per litre and 3220 grams per U.S. gallon. The S.G. can vary but the figure given is commonly used.)
Also, for a more accurate figure multiply the answer by 1.03-1.05 to account for drive train losses. In this example 48.5 x 1.03 = 50 litres/hour."